916 Checkerboard V1 Codehs Fixed Here
916 Checkerboard v1 Codehs Fixed
The 916 Checkerboard problem on CodeHS is a classic challenge that requires creating a checkerboard pattern using a loop. Here is a fixed and well-documented solution:
2. Algorithm and Logic
To draw a checkerboard, we use nested loops. The logic follows these steps: 916 checkerboard v1 codehs fixed
Create an 8×8 checkerboard where alternating squares are red and black, starting with red in the top-left. 916 Checkerboard v1 Codehs Fixed The 916 Checkerboard
Common errors & fixes:
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# 1. Initialize the 8x8 grid with all 0s grid = [] for i in range(8): grid.append([0] * 8) # 2. Use a nested loop to set specific rows to 1 for i in range(8): # Only modify the top 3 (i < 3) or bottom 3 (i > 4) rows if i < 3 or i > 4: for j in range(8): grid[i][j] = 1 # 3. Print the board using the provided function # (Make sure print_board is defined or provided by CodeHS) print_board(grid)Use code with caution. Copied to clipboard Proper Write-Up / Logic If (row + column) % 2 == 0 → Red Else → Black- If
(row + column) % 2 == 0→ Red - Else → Black
Apply Checkerboard LogicInside a nested loop, use the mathematical property of a checkerboard: an element should be if the sum of its row and column indices is an even number. Example: At
board[0][0], (even), so it becomes Example: Atboard[0][1], (odd), so it remains - If